1次元配列を関数に渡す


#include <stdio.h>

int sumA( int* a )
{
 int sum = 0;
 while ( *a != -999 ) {
  sum += *a;
  a++;
 }
 return sum;
}

int sumB( int* a )
{
 int i = 0, sum = 0;
 while ( a[ i ] != -999 ) {
  sum += a[ i ];
  i++;
 }
 return sum;
}

void main()
{
 int a[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, -999 };

 printf( "%d\n", sumA( a ) );
 printf( "%d\n", sumB( a ) );
}

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