2次元配列を関数に渡す


#include <stdio.h>

int sum( int* a )
{
 int i = 0, sum = 0;
 while ( *a != -999 ) {
  sum += *a;
  a++;
 }
 return sum;
}

void main()
{
 int a[][4] = { { 1, 2, 3, 0 }
        , { 4, 5, 6, 0 }
        , { 7, 8, 9, -999 } };

 printf( "%d\n", sum( a[0] ) );
}

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