1次元配列を関数に渡す
#include <stdio.h>
int sumA( int* a )
{
int sum = 0;
while ( *a != -999 ) {
sum += *a;
a++;
}
return sum;
}
int sumB( int* a )
{
int i = 0, sum = 0;
while ( a[ i ] != -999 ) {
sum += a[ i ];
i++;
}
return sum;
}
void main()
{
int a[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, -999 };
printf( "%d\n", sumA( a ) );
printf( "%d\n", sumB( a ) );
}